6x^2+12=18+35x

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Solution for 6x^2+12=18+35x equation:



6x^2+12=18+35x
We move all terms to the left:
6x^2+12-(18+35x)=0
We add all the numbers together, and all the variables
6x^2-(35x+18)+12=0
We get rid of parentheses
6x^2-35x-18+12=0
We add all the numbers together, and all the variables
6x^2-35x-6=0
a = 6; b = -35; c = -6;
Δ = b2-4ac
Δ = -352-4·6·(-6)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-37}{2*6}=\frac{-2}{12} =-1/6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+37}{2*6}=\frac{72}{12} =6 $

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